Current density

From Wikipedia, the free encyclopedia

Current density is a measure of the density of electrical current. It is defined as a vector whose magnitude is the electric current per cross-sectional area. In SI unit, the current density is measured in amperes per square meter.

Electrical current is a coarse, average quantity that tells what is happening in an entire wire. If we want to describe the distribution of the charge flow, we use the concept of the current density:

\vec{J}=nq\vec{v_d}=\rho \vec{v_d} \!\

where

\vec{J} \!\ is the current density vector (SI unit amperes per square metre)
n \!\ is the particle density in count per volume (SI unit m-3)
q \!\ is the individual particles' charge (SI unit coulombs)
\rho = nq \!\ is the charge density (SI unit coulombs per cubic metre)
\vec{v_d} \!\ is the particles' average drift velocity (SI unit meters per second)

The current flowing through a surface S can be calculated by the following relation:

I=\int_S{  \vec{J} \cdot  d\vec{S}}

– where the current is in fact the integral of the dot product of the current density vector and the differential surface element d \vec{S}, i.e. the net flux of the current density vector field flowing through the surface S.

The current density is an important parameter in Ampère's law (one of Maxwell's equations), which show the direct link between current density and magnetic field strength.

Current density is an important consideration in the design of electrical and electronic systems. Most electrical conductors have a finite, positive resistance, making them dissipate power in the form of heat. The current density must be kept sufficiently low to prevent the conductor from melting or burning up, or the insulating material failing. In superconductors excessive current density may generate a strong enough magnetic field to cause spontaneous loss of the superconductive property.

From the divergence theorem,

\int_S{ \vec{J} \cdot \vec{S} dS} = \int_V{(\vec{\bigtriangledown} \cdot \vec{J}) dV}

since charge is conserved,

\int_V{(\vec{\bigtriangledown} \cdot \vec{J}) dV} = -\frac{d}{dt} \int_V{\rho dV} = - \int_V{\Big( \frac{\partial \rho}{\partial t} \Big) dV}

Since this is valid for any volume,

\vec{\bigtriangledown} \cdot \vec{J} = - \frac{\partial \rho}{\partial t}.

which is also called the continuity equation.[1]

  1. ^ Griffiths, D.J., Introduction to Electrodynamics, page 213, Prentice-Hall International, 1999.

  • [1] - A short explanation of the current density
Advanced Search
Included Web Search Engines


Safe Search

close

Top Matching Results

Occasionally Search.com will highlight specialized results that are based on the context of your query. Examples of specialized results include specific links to news, images, or video.

Top Matching Results may highlight information from other Search.com pages, content from the CNET Network of sites, or third party content. The listings are based purely on relevance. Search.com does not receive payment for listings in this section but our partners that provide this data may get paid for listing these products.

Sponsored Links

This section contains paid listings which have been purchased by companies that want to have their sites appear for specific search terms and related content. These listings are administered, sorted and maintained by a third party and are not endorsed by Search.com.

Search Results

Search.com sends your search query to several search engines at one time and integrates the results into one list which has been sorted by relevance using Search.com's proprietary algorithm. You can customize the list of search engines included in your metasearch from the preferences.

The search engines that are used in your metasearch may allow companies to pay to have their Web sites included within the results. To view the Paid Inclusion policy for a specific search engine, please visit their Web site. Search.com does not accept payment or share revenue with any search engine partner for listings in this section.