Electric displacement field

From Wikipedia, the free encyclopedia

(Redirected from Electric displacement)
Jump to: navigation, search

In physics, the electric displacement field or electric induction[citation needed] is a vector field \mathbf{D} that appears in Maxwell's equations. It accounts for the effects of unbound charges within materials. "D" stands for "displacement," as in the related concept of displacement current in dielectrics.

In general, D is defined by the relation

\mathbf{D} = \varepsilon_{0} \mathbf{E} + \mathbf{P}

where E is the electric field, \varepsilon_{0} is the vacuum permittivity, and P is the polarization density of the material.

If P can be written as a linear function of E, which is the case in most materials, it can be written as

\mathbf{P} = \chi \varepsilon_{0} \mathbf{E},

and by

\mathbf{D} = \varepsilon_{0} \mathbf{E} + \mathbf{P} = \varepsilon_{0}(1 + \chi) \mathbf{E} \equiv \varepsilon \mathbf{E}

it yields

\mathbf{D} = \varepsilon \mathbf{E}

where \varepsilon is the permittivity of the material. In linear isotropic media this will be a constant, and in linear anisotropic media it will be a rank 2 tensor (a matrix). χ is called the electric susceptibility.

Consider an infinite parallel plate capacitor placed in space (or in a medium) with no free charges present except on the capacitor. In SI units, the charge density on the plates is equal to the value of the D field between the plates. This follows directly from Gauss's law, by integrating over a small rectangular box straddling each plates of the capacitor:

\oint_A \mathbf{D} \cdot d\mathbf{A} = Q

On the sides of the box, d\mathbf{A} is perpendicular to the field, so that part of the integral is zero, leaving, for the space inside the capacitor where the effect of the two plates adds:

|\mathbf{D}| = \frac{Q}{A}

which is the charge density on the plate. Outside the capacitor, the two plates effect compensate each other and |\mathbf{D}| = 0.

In the standard SI system of units D is measured in coulombs per square meter (C/m²).

This choice of units results in one of the simplest forms of the Ampère-Maxwell equation:

\nabla \times \mathbf{H} = \mathbf{J} + \frac{\partial \mathbf{D}}{\partial t}

If one chooses both B and H to be measured in teslas, and E and D to be measured in newtons per coulomb, then the formula is modified to be:

\nabla \times \mathbf{H} = \mu_0 \mathbf{J} + \frac{1}{c^2} \frac{\partial \mathbf{D}}{\partial t}

Therefore it is seen as being preferential to express B & H, and E & D in different sets of units.

Choice of units has differed in history, for instance in the electromagnetic system of scientific units, in which the unit of charge is defined such that 1 / 4\pi\varepsilon_0 = 1 (dimensionless), E and D are expressed in the same units.

Advanced Search
Included Web Search Engines


Safe Search

close

Top Matching Results

Occasionally Search.com will highlight specialized results that are based on the context of your query. Examples of specialized results include specific links to news, images, or video.

Top Matching Results may highlight information from other Search.com pages, content from the CNET Network of sites, or third party content. The listings are based purely on relevance. Search.com does not receive payment for listings in this section but our partners that provide this data may get paid for listing these products.

Sponsored Links

This section contains paid listings which have been purchased by companies that want to have their sites appear for specific search terms and related content. These listings are administered, sorted and maintained by a third party and are not endorsed by Search.com.

Search Results

Search.com sends your search query to several search engines at one time and integrates the results into one list which has been sorted by relevance using Search.com's proprietary algorithm. You can customize the list of search engines included in your metasearch from the preferences.

The search engines that are used in your metasearch may allow companies to pay to have their Web sites included within the results. To view the Paid Inclusion policy for a specific search engine, please visit their Web site. Search.com does not accept payment or share revenue with any search engine partner for listings in this section.